Sunday, September 23, 2012

2nd Quarter Chemistry 2012: Polarity of Molecules


Polarity Worksheet

For each of the following pairs of molecules, determine which is most polar and explain your reason for making this choice:

1)        carbon disulfide                   OR                  sulfur difluoride




2)        nitrogen trichloride              OR                  oxygen dichloride




3)        boron trihydride                    OR                  ammonia




4)        chlorine                                 OR                  phosphorus trichloride




5)        silicon dioxide                      OR                  carbon dioxide




6)        CH4                             OR                  CH2Cl2




7)        silicon tetrabromide                        OR                  HCN




8)        nitrogen trifluoride               OR                  phosphorus trifluoride




SPOILER ALERT!!!    SPOILER ALERT!!!    SPOILER ALERT!!!    SPOILER ALERT!!!

ANSWERS: 

1)        carbon disulfide                   OR                  sulfur difluoride
         carbon disulfide is nonpolar



2)        nitrogen trichloride              OR                  oxygen dichloride
            both are polar, but oxygen dichloride is less symmetric than nitrogen trichloride, making it more polar.



3)        boron trihydride                  OR                  ammonia
         boron trihydride is nonpolar.



4)        chlorine                                 OR                  phosphorus trichloride
            chlorine is nonpolar



5)        silicon dioxide                      OR                  carbon dioxide
         It’s a tie, because both are nonpolar



6)        CH4                             OR                  CH2Cl2
            CH4 is nonpolar



7)        silicon tetrabromide                        OR                  HCN
         silicon tetrabromide is nonpolar



8)        nitrogen trifluoride               OR                  phosphorus trifluoride
            Both are polar and equally symmetric, but the difference in electronegativity between N-F is less than that between P-F

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