1. In a previous problem, the empirical formula of a compound of phosphorus and oxygen was found to be P2O5. Experimentation shows that the molar mass of this compound is 283.89g/mol. What is the compounds molecular formula?
2. Determine the molecular formula of the compound with an empirical formula of CH and a molar mass of 78.110 g/mol.
3. A sample with a molar mass of 34.00 g/mol is found to consist of 0.44g H and 6.92g O. Find its molecular formula.
4. If 4.04g of N combine with 11.46g O to produce a compound with a molar mass of 108.0 g/mol, what is the molecular formula of this compound?
5. The empirical formula for trichloroisocyanuric acid, the active ingredient in many household bleaches, is OCNCl. The molar mass of this compound is 232.41g/mol. What is the molecular formula of trichloroisocyanuric acid.
6. The molar mass of a compound is 92g/mol. Analysis of a sample of the compound indicates that it contains 0.606g N and 1.390g O. Find its molecular formula.
7. Determine the molecular formula of a compound with an empirical formula of NH2 and a formula mass of 32.06 g/mol.
Answers:
1. Empirical Formula = P2O5Empirical Mass = 2(31.0) + 5(16.0) = 142g
Molecular Mass = 283.89g.
2(P2O5) = P4O10
2. Empirical Formula = CHEmpirical Mass = 1(12.0) + 1(1.0) = 13g
Molecular Mass = 78.110 amu
6(CH) = C6H6
3.
Empirical Formula = HOEmpirical Mass = 1(1.0) + 1(16.0) = 17g
Molecular Mass = 34.00 amu
2(HO) = H2O2
4.
Empirical Formula = N2O5Empirical Mass = 2(14.0) + 5(16.0) = 108.0g
Molecular Mass = 108.0 amu
1(N2O5) = N2O5
5. Empirical Formula = OCNClEmpirical Mass = 16.0+12.0+14.0+35.5 = 77.5g
Molecular Mass = 232.41 amu
3(OCNCl) = O3C3N3Cl3
Empirical Formula = NO2Empirical Mass = 1(14.0) + 2(16.0) = 46.0g
Molecular Mass = 92 g
2(NO2) = N2O4
7. Empirical Formula = NH2Empirical Mass = 1(14.0) + 2(1.0) = 16g
Molecular Mass = 32.06 amu
2(NH2) = N2H4
